3h^2+48h-4,756=0

Solution for 3h^2+48h-4,756=0 equation:

3h^2+48h-4.756=0

a = 3; b = 48; c = -4.756;
Δ = b2-4ac
Δ = 482-4·3·(-4.756)
Δ = 2361.072
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-\sqrt{2361.072}}{2*3}=\frac{-48-\sqrt{2361.072}}{6}
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+\sqrt{2361.072}}{2*3}=\frac{-48+\sqrt{2361.072}}{6}
$